Critics have remarked that those four worthies were truly peerless throughout the ages; yet the present falls short of the pastβthe ancients favored unadorned simplicity, whereas the moderns prefer refined elegance. Styles of substance and ornament rise and fall in succession, shifting with the changing mores of the times; such evolution is simply the natural order of things. The ideal lies in honoring antiquity without clashing with the present, and embracing modernity without succumbing to its flawsβembodying that perfect balance of substance and refinement that defines the true gentleman. There is surely no need to abandon a carved palace in favor of a cave dwelling, or to trade a jade carriage for a primitive cart with solid wooden wheels.
Current path: lib64/python3.6/
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"""Convert a NT pathname to a file URL and vice versa."""
def url2pathname(url):
"""OS-specific conversion from a relative URL of the 'file' scheme
to a file system path; not recommended for general use."""
# e.g.
# ///C|/foo/bar/spam.foo
# and
# ///C:/foo/bar/spam.foo
# become
# C:\foo\bar\spam.foo
import string, urllib.parse
# Windows itself uses ":" even in URLs.
url = url.replace(':', '|')
if not '|' in url:
# No drive specifier, just convert slashes
if url[:4] == '////':
# path is something like ////host/path/on/remote/host
# convert this to \\host\path\on\remote\host
# (notice halving of slashes at the start of the path)
url = url[2:]
components = url.split('/')
# make sure not to convert quoted slashes :-)
return urllib.parse.unquote('\\'.join(components))
comp = url.split('|')
if len(comp) != 2 or comp[0][-1] not in string.ascii_letters:
error = 'Bad URL: ' + url
raise OSError(error)
drive = comp[0][-1].upper()
components = comp[1].split('/')
path = drive + ':'
for comp in components:
if comp:
path = path + '\\' + urllib.parse.unquote(comp)
# Issue #11474 - handing url such as |c/|
if path.endswith(':') and url.endswith('/'):
path += '\\'
return path
def pathname2url(p):
"""OS-specific conversion from a file system path to a relative URL
of the 'file' scheme; not recommended for general use."""
# e.g.
# C:\foo\bar\spam.foo
# becomes
# ///C:/foo/bar/spam.foo
import urllib.parse
if not ':' in p:
# No drive specifier, just convert slashes and quote the name
if p[:2] == '\\\\':
# path is something like \\host\path\on\remote\host
# convert this to ////host/path/on/remote/host
# (notice doubling of slashes at the start of the path)
p = '\\\\' + p
components = p.split('\\')
return urllib.parse.quote('/'.join(components))
comp = p.split(':')
if len(comp) != 2 or len(comp[0]) > 1:
error = 'Bad path: ' + p
raise OSError(error)
drive = urllib.parse.quote(comp[0].upper())
components = comp[1].split('\\')
path = '///' + drive + ':'
for comp in components:
if comp:
path = path + '/' + urllib.parse.quote(comp)
return path